3.155 \(\int \frac{1}{\log ^2(c (d+e x^3)^p)} \, dx\)

Optimal. Leaf size=16 \[ \text{Unintegrable}\left (\frac{1}{\log ^2\left (c \left (d+e x^3\right )^p\right )},x\right ) \]

[Out]

Unintegrable[Log[c*(d + e*x^3)^p]^(-2), x]

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Rubi [A]  time = 0.0035729, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{1}{\log ^2\left (c \left (d+e x^3\right )^p\right )} \, dx \]

Verification is Not applicable to the result.

[In]

Int[Log[c*(d + e*x^3)^p]^(-2),x]

[Out]

Defer[Int][Log[c*(d + e*x^3)^p]^(-2), x]

Rubi steps

\begin{align*} \int \frac{1}{\log ^2\left (c \left (d+e x^3\right )^p\right )} \, dx &=\int \frac{1}{\log ^2\left (c \left (d+e x^3\right )^p\right )} \, dx\\ \end{align*}

Mathematica [A]  time = 0.359393, size = 0, normalized size = 0. \[ \int \frac{1}{\log ^2\left (c \left (d+e x^3\right )^p\right )} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[Log[c*(d + e*x^3)^p]^(-2),x]

[Out]

Integrate[Log[c*(d + e*x^3)^p]^(-2), x]

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Maple [A]  time = 3.554, size = 0, normalized size = 0. \begin{align*} \int \left ( \ln \left ( c \left ( e{x}^{3}+d \right ) ^{p} \right ) \right ) ^{-2}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/ln(c*(e*x^3+d)^p)^2,x)

[Out]

int(1/ln(c*(e*x^3+d)^p)^2,x)

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Maxima [A]  time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{e x^{3} + d}{3 \,{\left (e p x^{2} \log \left ({\left (e x^{3} + d\right )}^{p}\right ) + e p x^{2} \log \left (c\right )\right )}} + \int \frac{e x^{3} - 2 \, d}{3 \,{\left (e p x^{3} \log \left ({\left (e x^{3} + d\right )}^{p}\right ) + e p x^{3} \log \left (c\right )\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/log(c*(e*x^3+d)^p)^2,x, algorithm="maxima")

[Out]

-1/3*(e*x^3 + d)/(e*p*x^2*log((e*x^3 + d)^p) + e*p*x^2*log(c)) + integrate(1/3*(e*x^3 - 2*d)/(e*p*x^3*log((e*x
^3 + d)^p) + e*p*x^3*log(c)), x)

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Fricas [A]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{1}{\log \left ({\left (e x^{3} + d\right )}^{p} c\right )^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/log(c*(e*x^3+d)^p)^2,x, algorithm="fricas")

[Out]

integral(log((e*x^3 + d)^p*c)^(-2), x)

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Sympy [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\log{\left (c \left (d + e x^{3}\right )^{p} \right )}^{2}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/ln(c*(e*x**3+d)**p)**2,x)

[Out]

Integral(log(c*(d + e*x**3)**p)**(-2), x)

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Giac [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\log \left ({\left (e x^{3} + d\right )}^{p} c\right )^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/log(c*(e*x^3+d)^p)^2,x, algorithm="giac")

[Out]

integrate(log((e*x^3 + d)^p*c)^(-2), x)